Aptitude Practice Questions

1.The ratio of the speed of a bus and a car is 2:5. The car covers a distance of 280 km in some time and the bus covers a distance of “d” km less in the same time. What is the distance covered by the bus?

112 km
144 km
168 km
132 km

Ans:-
Speed of bus and car (B/C)= 2/5
with 5 unit of speed (5x) if car can cover 280 km
i.e. 5x = 280
x= 56
the speed of bus is 2 units so 2*56 =112 KM

Answer. A 112 km

2. The sum of the present ages of Ajay and his wife Sushma is 82 years. Sushma’s present age is 28 years more than Sashank's, her son. If Sashank’s present age is 12 years, what will be the sum of ages of Sashank and his father after 4 years?

Options

56 years
60 Years
62 years
58 years

Ans :-
Ajay +Sushma =82
Sushma = Son+28
Son =12
Sushma =12+28=40
Ajay =82-40 =42
(Son+4)+(Ajay+4) = 42+4 + 12+4 = 62

Answer: Option C - 62

3.The table below shows the total number of 10th class students in 5 different schools (P,Q,R,S and T). and the ratio of the number of students Art, Commerce and Science respectively. The students study only the above given subjects in the class of each school.

School	TOTAL STUDENTS	Arts: Commerce: Science
P	240	1:2:3
Q	450	7:1:1
R	360	5:4:3
S	180	2:5:3
T	330	6:4:1

What is the total number of science students in school P, Q and R together?

Solution:-

P = 1x+2x+3x =240

6x =240

x= 40

Science = 3x= 120

Q =7x+1x+1x =450

9x=450

x=50

Science = x=50

R = 5x+4x+3x =360

12x= 360

x= 30

Science = 3x= 90

P+Q+R= 120+50+90 =260

Answer: Option D - 260

4. The speed of a train is 72km/hr. It crosses a pole in 14 sec. The train will cross a tunnel of length 400m in(sec)?

Length of train is distance covered in case of crossing a pole

Speed = 72 * 5/18 =20m/s

time=14 sec

Distance = 14*20 =280

Length of the train is 280 m

to cross the tunnel train has to travel distance of = length of train + length of tunnel

= 280 + 400

= 680

Time = Distance / Speed = 680 /20 = 34 sec

Ans - Option A - 34

5.A,B and C, together can complete work in 16 days. If A and B together can complete the work in 24 days, in how many days C alone can complete 75% of the work?

30 days

36 days

48 days

40 days

A+ B+ C = 16 days

Efficiency of A+B+C =1/ 16

A+B = 24 days

Efficiency of A+B = 1/24

Efficiency of C= (A+B+C ) - (A+B)

= 1/16 - 1/24

= 1/48

C alone can complete entire work (100%) in 48 days

100% = 48 days

75% = 75 * 48 /100 = 36 days

C can complete 75 % of work in 36 days

Answer: Option B - 36 days

6. Find the geometric mean of the data 5,75,9
A. 45
B. 5
C. 15
D. 9

Geometric Mean :-

GM= cube root (5 * 75 * 9)

= cube root (3375)

=15

Answer: Option C - 15

7.For doing a certain work the efficiency of A, B and C are in ratio 3:7:5. Working together they can complete the work in 21 days . B alone can complete the original work in:

A.30

B.45

C.42

D.28

Efficiency : 3x+ 7x +5x = 15 * 21 days = 315 units of works

Efficiency of B = 315 / 7 = 45

Answer- Option B - 45

8. Two numbers are in the ratio of 3:5 . If 3 is added to the first number and 9 is added to the 2nd number, their ratio becomes 4:7. The sum of the original numbers is.

120

150

105

135

3x + 3 / 5x + 9 = 4 /7
7 (3x+3) =4 (5x+9)
21x +21 = 20x + 36
x =36-21
x= 15

3x + 5x = 3 (15) +5 (15) =45 + 75 = 120

Ans - Option A - 120

9. Ankush bought (x+2) apples at the rate of Rs. 12 each. One apple got rotten during transportation and he sold all the remaining apples for Rs. 300. If the percentage profit made by Ankush in the whole transaction is 25%, find the number of apples sold by Ankush.

Cost Price = (x+2) * 12

1 is apple is rotten = ( x + 2 ) - 1 = x-1

No of apples Sold = x -1

Selling Price = 300

Profit = 25 %

Cost Price = (100 / 100+ profit )* Selling Price

= (100 / 125 ) * 300

= 240

No of apples = (x+2) * 12

240 = (x+2) * 12

240/12 = (x+2)

20 = (x+2)

Purchase 20 apples

1 apple is rotten x-1 = 20-1 = 19 apples were sold

Answer: Option A - 19.

10. The LCM and HCF of two numbers are 2016 and 6 respectively. If one of the numbers lies between 90 and 100 then the other numbers lie between what?

100 and 110

90 and 100

120 and 130

110 and 120

Ans:- HCF * LCM = 2 no's

HCF * LCM = 2016 * 6

As one of the no lies between 90 to 100 divide 2016 by all the no between 90 to 100 to check if divisible by any

Its divisible by 96

so 20 16 can be written as 96 *21

HCF * LCM = 2016 * 6

= 96 * 21 * 6

= 96 * 126

2016 and 6 are LCM and HCF of no's 96 and 126

the 2nd no lies in range of 120 to 130

Answer: Option C

11. The expenditure of Rashmi is equal to 225% of her savings. If her income increases by 20% and the expenditure increases by 40%, then her savings will __________.

Decrease by 25%
Decrease by 20%
Increase by 25%
Increase by 33 ⅓ %

Consider Rashmi Savings as 100 Rs

Saving Expenditure Income =Saving + Expenditure

100 225 325

Income increases by 20% so 20% of 325 is 65

Expenditure increases by 40% so 40 % of 225 is 90

Income =Saving + Expenditure Expenditure Saving

390 315 390-315=75

Saving decreased by 100 to 75

25 % decreased

Answer: Option A

12. A business lady bought 400 handbags. She sold 100 of them at a profit of 20% and the rest at 10% profit. Find the overall profit percentage.

12.5%
16.75%
19.75%
11.25%

Consider Selling Price of each bag as 1 Rs

CP of 100 bag = (100 /100 + profit % ) * SP
= (100 /100 + 20 ) * 100
= 83.33

CP of 300 bag = = (100 / 100 + profit % ) * SP
= (100 /100 + 10 ) * 300
= 272.72

CP of 400 bags = 83.33 + 272.72 = 356.05 Rs

SP of 400 bags = 400 Rs

Profit = SP - CP
= 400 - 356.05
= 43.95

Profit % = ( Profit / CP )* 100
= (43.95 / 356.05 ) * 100
= 12.37%

Answer:- a. 12.5%

Aptitude Practice Questions